Sweet Bonanza 1000 is a Pragmatic Play title, and the thing worth understanding before playing it is a shorter free-spins round with a twentyfold higher multiplier ceiling, which is a trade rather than an upgrade.
The gaps in the table are real gaps, not omissions.
How the Sweet Bonanza 1000 feature round works
The feature round is where the game actually pays.
The cluster and tumble mechanics are unchanged from the original. Two things move: the multiplier bombs now reach 1000x instead of 100x, and the free-spins round opens at 10 spins rather than 15, with three further scatters adding five more. Fewer spins carrying much larger multipliers is a deliberately narrower distribution, and it is why this carries a very high volatility label where the original carries medium to high.
Pragmatic Play publishes a maximum win of 25000x for this title, which is the ceiling on a single round rather than anything a session should be planned around.
Sweet Bonanza 1000 specifications
| Spec | Value |
|---|---|
| Provider | Pragmatic Play |
| Reels | 6 |
| Rows | 5 |
| Paylines | cluster pays, 8+ matching symbols anywhere |
| RTP | 96.53% |
| Volatility | very high |
| Max win | 25000x |
| Min stake | Not published |
The published RTP of 96.53% is a long-run average across millions of spins, not a rate that applies to an evening.
Confirmed to ship in three operator-selectable configurations: 96.53%, 95.52% and 94.51%.
Pragmatic Play describes it as very high volatility, which describes the shape of the results rather than their size.
What the maximum win figure actually means
The published 25000x ceiling on Sweet Bonanza 1000 describes the largest possible outcome of a single round relative to the stake. It is a boundary, not a target, and it says nothing about how often any outcome occurs. A game can carry a very high ceiling and still pay small amounts almost every time it pays at all.
Read the ceiling alongside the volatility rather than on its own. The two together describe the shape of the game; either one by itself is close to meaningless.
Why no RTP appears on this page
Pragmatic Play does not publish a return-to-player figure for Sweet Bonanza 1000. That is not an omission on this page: the studio’s own game listing has no RTP field on any title, and the percentages circulating on comparison sites come from third-party databases that disagree with each other by up to two points on the same game.
Quoting one of those numbers would mean presenting an unverifiable figure as a fact, so this page states the specifications Pragmatic Play does publish and leaves the rest blank. If an RTP matters to a decision, the in-game information screen is the only place it can be read directly.
Where Sweet Bonanza 1000 sits next to its siblings
The original Sweet Bonanza caps multipliers at 100x across 15 free spins and publishes a 21,100x maximum. This one reaches 1000x across 10 spins and publishes 25,000x. The maximum moves by under 20 per cent while the multiplier ceiling moves by a factor of ten, which tells you the extra headroom is spent on rarity rather than on size.
Playing Sweet Bonanza 1000 at BOSS77
Sweet Bonanza 1000 is a Pragmatic Play title, which is a fact about the game rather than about any operator. No BOSS77 lobby was reachable while this site was built, so this page does not claim Sweet Bonanza 1000 sits in the BOSS77 catalogue today. The lobby itself is the only place that can answer it.
FAQ
What is the RTP of Sweet Bonanza 1000?
Pragmatic Play publishes 96.53% for this title. That is a long-run theoretical average, not a rate that applies to a single session.
What is the maximum win on Sweet Bonanza 1000?
25000x is the published ceiling for a single round. It is a maximum, not an expectation.
How volatile is Sweet Bonanza 1000?
Pragmatic Play describes it as very high volatility. That describes how results are distributed, not how much the game returns.
Is Sweet Bonanza 1000 available at BOSS77?
Not confirmed. No BOSS77 lobby was reachable while this site was built, so this page describes the game as Pragmatic Play publishes it rather than asserting which operator carries it.